Date and Time Converter

Quiz>

Computer date and time format consists only of numbers,

for example: 21.05.2018 16:30

Humans prefer to see something like this: 21 May 2018 year, 16 hours 30 minutes

Your task is simple - convert the input date and time from computer format into a "human" format.

 

example

 

Input:

Date and time as a string

 

Output:

The same date and time, but in a more readable format

 

Example:

date_time("01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes"
date_time("19.09.2999 01:59") == "19 September 2999 year 1 hour 59 minutes"
date_time("21.10.1999 18:01") == "21 October 1999 year 18 hours 1 minute"
# NB: words "hour" and "minute" are used only when time is 01:mm (1 hour) or hh:01 (1 minute).
# In other cases it should be used "hours" and "minutes".

 

How it is used:

To improve the understanding between computers and humans.

 

Precondition:

0 < date <= 31

0 < month <= 12

0 < year <= 3000

0 < hours < 24

0 < minutes < 60

 

def date_time(time: str) -> str:
    #replace this for solution
    return time

if __name__ == '__main__':
    print("Example:")
    print(date_time('01.01.2000 00:00'))

    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert date_time("01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes", "Millenium"
    assert date_time("09.05.1945 06:30") == "9 May 1945 year 6 hours 30 minutes", "Victory"
    assert date_time("20.11.1990 03:55") == "20 November 1990 year 3 hours 55 minutes", "Somebody was born"
    print("Coding complete? Click 'Check' to earn cool rewards!")

 

Solve>

1. datetime : 날짜와 시간을 함께 저장하는 패키지

from datetime import datetime

 

2. datetime.strptime : 현재일의 년월일을 문자열로 구한다

def date_time(time: str):
    t = datetime.strptime(time, '%d.%m.%Y %H:%M')

 

3. datetime.strftime : 포맷 문자열에 의해 제어되는 날짜와 시간을 나타내는 문자열을 반환

def date_time(time: str):
    y, m, d, h, mi = t.year, datetime.strftime(t, '%B'), t.day, t.hour, t.minute

 

4. n이 1이 아니면 s 1이면 공백

def suffix(n):
        return 's' if n != 1 else ''

 

5. 포맷 문자열 리터럴로 출력

def date_time(time: str):
    return f'{d} {m} {y} year {h} hour{suffix(h)} {mi} minute{suffix(mi)}'

 

Code>

def date_time(time: str):
    t = datetime.strptime(time, '%d.%m.%Y %H:%M')
    y, m, d, h, mi = t.year, datetime.strftime(
        t, '%B'), t.day, t.hour, t.minute

    def suffix(n):
        return 's' if n != 1 else ''

    return f'{d} {m} {y} year {h} hour{suffix(h)} {mi} minute{suffix(mi)}'

 

Example>

if __name__ == '__main__':
    print("Example:")
    print(date_time('01.01.2000 00:00'))

    # These "asserts" using only for self-checking and not necessary for auto-testing
    assert date_time(
        "01.01.2000 00:00") == "1 January 2000 year 0 hours 0 minutes", "Millenium"
    assert date_time(
        "09.05.1945 06:30") == "9 May 1945 year 6 hours 30 minutes", "Victory"
    assert date_time(
        "20.11.1990 03:55") == "20 November 1990 year 3 hours 55 minutes", "Somebody was born"
    print("Coding complete? Click 'Check' to earn cool rewards!")

 

Result>

Example:

1 January 2000 year 0 hours 0 minutes

Coding complete? Click 'Check' to earn cool rewards!