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Days Between

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How old are you in a number of days?

It's easy to calculate - just subtract your birthday from today.

We could make this a real challenge though and count the difference between any dates.

 

You are given two dates as an array with three numbers - a year, month and day. 

 

For example:

19 April 1982 will be (1982, 4, 19). You should find the difference in days between the given dates.

For example between today and tomorrow = 1 day. The difference will always be either a positive number or zero,

so don't forget about the absolute value.

 

Input:

Two dates as tuples of integers.

 

Output:

The difference between the dates in days as an integer.

 

Example:

days_diff((1982, 4, 19), (1982, 4, 22)) == 3
days_diff((2014, 1, 1), (2014, 8, 27)) == 238

 

How it is used: 

Python has batteries included, so in this mission you’ll need to learn how to use completed modules so that you 

don't have to invent the bicycle all over again.

 

Precondition:

Dates between 1 january 1 and 31 december 9999. Dates are correct.

 

def days_diff(a, b):
    # your code here
    return None


if __name__ == '__main__':
    print("Example:")
    print(days_diff((1982, 4, 19), (1982, 4, 22)))

    # These "asserts" are used for self-checking and not for an auto-testing
    assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
    assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
    assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
    print("Coding complete? Click 'Check' to earn cool rewards!")

 

Solve>

1. datetime 모듈 임포트

from datetime import datetime

 

2. datetime를 사용하여서 년 월 일을 지정한다.

   각 년 / 월 / 일은 입력되는 인덱싱 번호로 추출한다.

   출력값은 year-month-day 00:00:00 로 나온다.

   날짜2 - 날짜1이므로 날짜1을 먼저 가져온다.

def days_diff(date1, date2):
    date1 = datetime(year=date1[0], month=date1[1], day=date1[2])

 

3. 이어서 날짜2를 가져온다.

def days_diff(date1, date2):
    date2 = datetime(year=date2[0], month=date2[1], day=date2[2])

 

4. date2에서 date1의 날짜를 빼면 되므로 절대값을 줘서 계산 후 반환 한다.

def days_diff(date1, date2):
    return abs((date2 - date1).days)

 

Code>

def days_diff(date1, date2):
    date1 = datetime(year=date1[0], month=date1[1], day=date1[2])
    
    date2 = datetime(year=date2[0], month=date2[1], day=date2[2])
    
    return abs((date2 - date1).days)

 

Example>

if __name__ == '__main__':
    print("Example:")
    print(days_diff((1982, 4, 19), (1982, 4, 22)))

    # These "asserts" are used for self-checking and not for an auto-testing
    assert days_diff((1982, 4, 19), (1982, 4, 22)) == 3
    assert days_diff((2014, 1, 1), (2014, 8, 27)) == 238
    assert days_diff((2014, 8, 27), (2014, 1, 1)) == 238
    print("Coding complete? Click 'Check' to earn cool rewards!")

 

Result>

Example:

3

Coding complete? Click 'Check' to earn cool rewards!

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