Quiz>
You are given a string and two markers (the initial and final).
You have to find a substring enclosed between these two markers.
But there are a few important conditions:
The initial and final markers are always different.
If there is no initial marker, then the first character should be considered the beginning of a string.
If there is no final marker, then the last character should be considered the ending of a string.
If the initial and final markers are missing then simply return the whole string.
If the final marker comes before the initial marker, then return an empty string.
Input: Three arguments. All of them are strings. The second and third arguments are the initial and final markers.
Output:
A string.
Example:
between_markers('What is >apple<', '>', '<') == 'apple'
between_markers('No[/b] hi', '[b]', '[/b]') == 'No'
How it is used:
for parsing texts
Precondition:
can't be more than one final marker and can't be more than one initial. Marker can't be an empty string
def between_markers(text: str, begin: str, end: str) -> str:
"""
returns substring between two given markers
"""
# your code here
return ''
if __name__ == '__main__':
print('Example:')
print(between_markers('What is >apple<', '>', '<'))
# These "asserts" are used for self-checking and not for testing
assert between_markers('What is >apple<', '>', '<') == "apple", "One sym"
assert between_markers("<head><title>My new site</title></head>",
"<title>", "</title>") == "My new site", "HTML"
assert between_markers('No[/b] hi', '[b]', '[/b]') == 'No', 'No opened'
assert between_markers('No [b]hi', '[b]', '[/b]') == 'hi', 'No close'
assert between_markers('No hi', '[b]', '[/b]') == 'No hi', 'No markers at all'
assert between_markers('No <hi>', '>', '<') == '', 'Wrong direction'
print('Wow, you are doing pretty good. Time to check it!')
Solve>
1. 시작 텍스트가 문자열에 있으면 시작 인덱스 번호는 find를 통해 찾은 문자열의 위치 + 시작 텍스트의 원소 갯수
def between_markers(text: str, begin: str, end: str):
if begin in text:
begin_index = text.find(begin) + len(begin)
2. 그 외에 경우에는 시작 번호는 0
def between_markers(text: str, begin: str, end: str):
else:
begin_index = 0
3. 끝 텍스트가 문자열에 있으면 find를 통해 찾은 문자열의 위치가 끝 인덱스 번호
def between_markers(text: str, begin: str, end: str):
if end in text:
end_index = text.find(end)
4. 그 외에 경우에는 문자열의 원소 갯수
def between_markers(text: str, begin: str, end: str):
else:
end_index = len(text)
5. 이렇게 찾아낸 인덱스번호를 통해 슬라이싱 작업
def between_markers(text: str, begin: str, end: str):
return text[begin_index:end_index]
Code>
def between_markers(text: str, begin: str, end: str):
if begin in text:
begin_index = text.find(begin) + len(begin)
else:
begin_index = 0
if end in text:
end_index = text.find(end)
else:
end_index = len(text)
return text[begin_index:end_index]
Example>
if __name__ == '__main__':
print('Example:')
print(between_markers('What is >apple<', '>', '<'))
# These "asserts" are used for self-checking and not for testing
assert between_markers('What is >apple<', '>', '<') == "apple", "One sym"
assert between_markers("<head><title>My new site</title></head>",
"<title>", "</title>") == "My new site", "HTML"
assert between_markers('No[/b] hi', '[b]', '[/b]') == 'No', 'No opened'
assert between_markers('No [b]hi', '[b]', '[/b]') == 'hi', 'No close'
assert between_markers(
'No hi', '[b]', '[/b]') == 'No hi', 'No markers at all'
assert between_markers('No <hi>', '>', '<') == '', 'Wrong direction'
print('Wow, you are doing pretty good. Time to check it!')
Result>
Example:
apple
Wow, you are doing pretty good. Time to check it!
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